5p^2-26p+2=0

Solution for 5p^2-26p+2=0 equation:

5p^2-26p+2=0

a = 5; b = -26; c = +2;
Δ = b2-4ac
Δ = -262-4·5·2
Δ = 636
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{636}=\sqrt{4*159}=\sqrt{4}*\sqrt{159}=2\sqrt{159}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2\sqrt{159}}{2*5}=\frac{26-2\sqrt{159}}{10}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2\sqrt{159}}{2*5}=\frac{26+2\sqrt{159}}{10}
$